2x^2+(4x)^2=360

Solution for 2x^2+(4x)^2=360 equation:

2x^2+(4x)^2=360

We move all terms to the left:

2x^2+(4x)^2-(360)=0

We add all the numbers together, and all the variables

6x^2-360=0

a = 6; b = 0; c = -360;
Δ = b2-4ac
Δ = 02-4·6·(-360)
Δ = 8640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8640}=\sqrt{576*15}=\sqrt{576}*\sqrt{15}=24\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{15}}{2*6}=\frac{0-24\sqrt{15}}{12}
=-\frac{24\sqrt{15}}{12}
=-2\sqrt{15}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{15}}{2*6}=\frac{0+24\sqrt{15}}{12}
=\frac{24\sqrt{15}}{12}
=2\sqrt{15}
$